【文档说明】广西钦州市2020-2021学年高二上学期期末教学质量监测物理试题答案.doc，共(2)页，208.000 KB，由小赞的店铺上传

转载请保留链接：https://www.doc5u.com/view-51bcd42c4ac8c5d84f754295fdc64d83.html

以下为本文档部分文字说明：

钦州市2020年秋季学期教学质量监测参考答案高二物理一、单项选择题（24分）题号12345678答案CDACBDAB二、多项选择题（16分）题号9101112答案BCACBDAD三、实验题（17分）13.（每空2

分，共8分）（1）甲（2）ABDFH（3）1.50.714.（每空3分，共9分）（1）A1如图所示（2）x910URI=−（Ω）四、计算题（43分）15.（8分）解析：设滑块与N点的距离为L，由动能定理可得，qEL－μmgL－mg·2R＝12mv2－0··········

···················3分小滑块在C点时，mg＝mv2R································································

3分解得v＝2m/s，L＝20m···································································2分16.（10分）解析：（1）根据闭合电路欧姆定律，12302A1410EIrRR===++++··············

2分220VUIR==·············································1分（2）电源的输出功率：WrIEIP562=−=····································

···2分（3）电场强度：20V200V/m0.1mUEd===········································1分粒子做类似平抛运动，有：tvL0=·······································

·········1分221aty=··············································································1分qEam=···························

···················································1分联立解得：mm1.28m101.28y-3==·············································1分17.（12分）

解析：(1)粒子在电场中加速，由动能定理有：212qUmv=····················2分解得：2qUvm=······································································2分(2

)粒子在磁场中的运动轨迹刚好与PQ相切时的轨道半径，是粒子从边界MN离开磁场最大轨道半径，如图由几何知识得：+=30sinrrd········································2分粒子在磁场中做圆周运动，洛伦兹力提

供向心力，2mvqvBr=···2分得：322mUBdq=························2分粒子最终从磁场边界MN离开磁场，磁感应强度：322mUBdq···········2分18.（13分）解析：（1）根据法拉第电磁感应定律，得感应电动势为：BLvE

=·················1分根据闭合电路的欧姆定律，得感应电流为：EIRr=+····················1分导体棒受到的安培力为：FBIL=安···········································1分导体棒做匀速运动

，处于平衡状态，由平衡条件得：sinFmgBIL=+···········································2分代入数据解得：smv/4=····················································

····1分（2）金属棒运动过程，由能量守恒定律得：21sin2FsmgsmvQ=++····3分电阻R产生的热量为：RRQQRr=+···········································2分代入数据解得：1.28RQ=J······

·················································2分