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2020～2021学年度湘鄂冀三省七校联考高一物理参考答案123456789101112CCDBDBCAABACADBC13.2td2121ttttdtd（每空2分）14.80.02sE点0.1412小于（每空2分）1

5.（7分）解：sAD=sAB+sBC+sCD=2200m··················（3分）xAC=BCABss=1000m··················（2分）xAD=xAC+xCD=1

800m··················（2分）16.（9分）解:(1)0txv··················（3分）(2)m/s33.3ts平均速率（均保留两位小数）············（3分）(3)201.30m/stvvtva···········

·······（3分）17.（14分）解：（1）s/m25-txv··················（2分）s=200m··················（1分）m/s25ts平均速率··················（2分）（2）201m/stvvtva·······

···········（4分）（3）s/m62002atvv··················（2分）m/s626vv··················（1分）s/m28668atvv··················（2分）18.解：（1）有几何关系可知

：m6.33xdx总··················（3分）s/m12txv总··················（2分）12m/s=43.2km/h故车辆已经超速··················（2分）（2）由图12知第一次超声波发出到被车辆反射时的时间

s2.01t··················（1分）此时车辆距测速仪的距离m6811tvx声··················（1分）由图12知第二次超声波发出到被车辆反射时的时间s12.02t··················（1分）

此时车辆距测速仪的距离m8.4022tvx声··················（1分）第一次超声波反射到第二次超声波反射车辆运动的时间和位移分别为s76.0t··················（1分）m2.27-212xxx··················（1分）车辆的速度s

/m79.35txv（一位两位小数均可）·············（2分）35.79m/s=128.8km/h故该车辆超速··················（1分）