【文档说明】广西钦州市2019-2020学年高二下学期期末教学质量监测数学(文)试题扫描版含答案.doc,共(7)页,2.614 MB,由管理员店铺上传
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钦州市2020年春季学期教学质量监测参考将答案高二数学(文科)一、选择题答案:(每小题5分,共60分)题号123456789101112答案BBDDCCDABBCD二、填空题答案:(每小题5分,共20分
)13.(1,2);14.5;15.2;16.8月份利润最低(或“3月份和10月份利润最高”等其他正确结论)三、解答题:本大题共6题,共70分.解答应写出文字说明、证明过程或演算步骤.17.证明:要证511313只须证22511313····
····································································2分只须证525511323913·····························
·········································.4分只须证5539······························································
·································6分只须证5539·····························································
····································8分因为5539成立所以511313·····················································
············10分18.解:(1)所有感染病毒的小白鼠共有50只,其中注射疫苗的共有y只,∴1505yP·································································
············································2分∴10,501040,yx402060,301040,mn·····························4分∴22列联表如下:未感染病毒感染病毒总计
未注射疫苗204060注射疫苗301040总计5050100······································································
·······························6分(2)∵22100(20103040)1005016.6675050604063K····································10分∵16.6676.635∴有99%把握认为
注射此种疫苗对预防新型冠状病毒有效.························12分19.解:(1)(1)∵cosx,siny,·························································2分∴1C的极坐标方程为si
n2.·······························································4分(2)∵直线3C的极坐标方程为6πR∴124sin6π,··············
······················································································7分24sin()23,66···························
·······························································10分∴21423MN····················
·······························································12分20.解:∵()|2|1fxxx,()7fx∴①当1x时,原不等式可化为217,x解得[3,1]x;········
··················3分②当12x时,原不等式可化为37,解得(1,2)x;···································6分③当2x时,不等式可化为217,x解得[2,4]x
;··········································9分综上,原不等式的解集为[3,4]······································································
·····12分21.解:(1)∵32cos,2sinxy∴2222(3)2cos2sin4xy∴曲线C的直角坐标方程22(3)4xy···································
····························4分(2)∵直线l的参数方程为222,22xtyt(t为参数)∴直线l与x轴交于点(2,0)P·······························
·················································6分将222,22xtyt代入圆C的方程22(3)4xy,整理得2230,tt122,tt12·3tt·
····································································································8分由参数的几何意义得1212PMPNtttt21212(
)4tttt2(2)4(3)14.∴14MNPMPN·········································································12分22.解:(1)由表中数据得,23453.54x
,26394954424y,∴41421ˆ9.4iiiiixxyybxx,429.43.59.1aybx,∴回归方程为9.49.1yx.······················
·····························································6分(2)年资金投入量为7.5万元时,9.47.59.179.6y(万元);····················8分(3)解9.49.1100x,·······
·······················································································10分得90.99.4x∵90.99.679.4∴若年市场销售额
超过100万,那么年资金投入量至少要9.67万元.··········12分