【文档说明】山东省济南市2020-2021学年高二下学期期末考试物理试题答案.docx，共(3)页，132.105 KB，由小赞的店铺上传

转载请保留链接：https://www.doc5u.com/view-925280b6e5739352197fc6d6d0b1ff34.html

以下为本文档部分文字说明：

高二物理参考答案一、单项选择题：本题共8个小题，每小题3分，共24分。1．B2．A3．C4．D5．B6．C7．D8．A二、多项选择题：本题包括4小题，每小题4分，共16分。9．BD10．BCD11．BC12．AD三、非选择题：本题共6个小题，满分60分。13．(1)ABD(2分，漏选得1

分，错选不得分)(2)B(2分)(3)1.16×10－2(1.14×10－2～1.18×10－2之间都对)(2分)；6×10－10(2分)14．(1)BC(2分，漏选得1分，错选不得分)(2)①tn(2分)

③2224πtTLgn=+(2分)④24πk(2分)15．解：(1)A质点开始振动的方向沿y轴负方向，故第二次出现波峰经历的时间t1=314T解得T=0.4s·······························(2分)由图可得λ=4m∴10

λvT==m/s················(2分)(2)B点第一次出现波谷的时刻为209xtT.v=+=s(2分)B走过的路程为为s=5A=50cm····················(2分)16．(1)位移最大时，加速度最大，m所

受静摩擦最大。对整体列牛顿第二定律方程有：()kAMma=+·······························(1分)∴()kAaMm=+对m有：f=ma··································(1分)µmg≥f················

····················(1分)解得：()kAμMmg+····················(1分)(2)对系统，由能量守恒可得：()2221112222AkAkMmv=++········

·············(2分)解得：32AkvMm=+·····································(2分)17．解：(1)由题意可知，出射角r=45o····················(1

分)sinsinrni=·····································(2分)解得：32sin10i=······························(1分)(2)临界角1sinCn=····························

·········(2分)解得：C=37o要使光线在AB、AC界面均发生全反射，需满足37oθ90o－θ≥37o可得：37o≤θ≤53o过P点做AB垂线交于Q，由几何关系得：PQ=aQM=a3tan374oa=································(3分)在

AB边上的入射角β=53o故在ΔPQN中，由几何关系可得：QN=a4tan533oa=··············(2分)综上所述，符合要求的区域为4373412MNaaa=−=·························(2分)18．(1)取上部气缸中的气体作为研究对象，由波意尔定

律得：01222LpLSpS=······························①(2分)解得：p1=2p0······························(1分)根据1

20010hppp=+可得h1=10m(1分)(2)设B活塞相对气缸移动的距离为x1，对两部分气体分别由波意尔定律得：0212210LpLSpSxS=+························②(2

分)()0214pLSpLxS=−·······························③(1分)联立②③可解得：205pp=································(1分)∴h2=40m·············

·······································(1分)(3)设A活塞恰好移动至上部气缸底端时水深为H，此时B活塞相对气缸移动的距离为x2，则对两部分气体分别由波意尔定律得：0322pLSpxS=·························④(1分)(

)0324pLSpLxS=−·····················⑤(1分)联立④⑤可解得：23Lx=306pp=(2分)∴H=50m···································

············(1分)此后随着水深的增加，A活塞和B活塞的位置不再便化故水深60m处，稳定后活塞B相对气缸N移动的距离23Ldx==(1分)