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高二数学参考答案一、选择题每题4分题号123456789答案AABCBBACD二、填空题每题4分10.4π11.xy2=12.22313.2或3−(只有1个答案正确,不得分)14.()10222=+−yx(或06422=−−+xyx)15.33三、解答题16.(本小题满分8分)(Ⅰ)圆C
的圆心)2,1(,...............................................2分半径为5=r..............................................
.......4分(Ⅱ)因为2200BACBA+++=yxd................................5分210=...................................................6分且222drAB−=...
.........................7分解得弦AB的长为10..........................8分17.(本小题满分10分)(Ⅰ)因为+==22222cbaac,............................
...2分又11222=+ba,所以==22ba,则椭圆C的方程为12422=+yx;..............4分(Ⅱ)设A),(11yx、B),(22yx、)0,2(D,由题意:=+−=124222
yxkxy,解得048)21(22=+−+kxxk,............5分因为0,解得2222−kk或,又+=+=+221221214218kxxkkxx,.............6分且1−=DBDAkk,....
.................7分即120202211−=−−−−xyxy,............8分又−=−=222211kxykxy,解得31==kk或(不合题意,舍去),............9分则直线l的方程为23−=xy。...
.........10分18.(本小题满分10分)(Ⅰ)由题意:=+=+802021111qaqaqaa,......................................2分解得:==441qa,.
.....................................4分则数列na的通项公式为:nnna4441==−;...................5分(Ⅱ)由题意:nbnn+=4,...................6分因为nnbbbb++++=321S
)321()4444(321nn+++++++++=..................8分2)1(41)41(4nnn++−−=...................10分2)14(342nnn++−=。(19)(本小题满分12分)(Ⅰ)依题意,以点C
为原点建立空间直角坐标系(如图),可得)0,0,1(A,)0,1,0(B,)0,0,0(C,)2,21,21(M,)1,0,1(N,)2,0,1(1A,)2,1,0(1B,)2,0,0(1C。向量)1,1,1(−=BN,...............
...........2分则3||222=++=zyxBN;..........................4分(Ⅱ)向量)2,1,1(1−−=BA,向量)0,21,21(1=MC,因为21221111zzyxyxMCBA
++=,..................................6分0)2(211211−++−=0=....................................................7分所以MCBA11⊥;.
.................................................8分(Ⅲ)向量)2,1,1(1−−=BA,向量)2,0,1(1−−=CA,设),,(zyxn=为平面BCA1的法向量,则
==0011nCAnBA即=−−=−+−0202zxzyx,不妨令2−=x,可得)1,0,2(−=n为平面BCA1的一个法向量,....................9分又)0,0,1(=CA为平面BCB1的法向量,.......................
......10分于是有CAnCAnCAn=cos...............................................11分552=。.........................12分MNABC1A1B1Czx
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