2022届湖南省普通高中学业水平考试合格性考试模拟试题(长郡版,高二物理)(答案)

DOC
  • 阅读 4 次
  • 下载 0 次
  • 页数 3 页
  • 大小 48.213 KB
  • 2024-12-11 上传
  • 收藏
  • 违规举报
  • © 版权认领
下载文档3.00 元 加入VIP免费下载
此文档由【envi的店铺】提供上传,收益归文档提供者,本网站只提供存储服务。若此文档侵犯了您的版权,欢迎进行违规举报版权认领
2022届湖南省普通高中学业水平考试合格性考试模拟试题(长郡版,高二物理)(答案)
可在后台配置第一页与第二页中间广告代码
2022届湖南省普通高中学业水平考试合格性考试模拟试题(长郡版,高二物理)(答案)
可在后台配置第二页与第三页中间广告代码
2022届湖南省普通高中学业水平考试合格性考试模拟试题(长郡版,高二物理)(答案)
可在后台配置第三页与第四页中间广告代码
在线阅读已结束,您可下载此文档进行离线阅读 已有0人下载 下载文档3.00 元
/ 3
  • 收藏
  • 违规举报
  • © 版权认领
下载文档3.00 元 加入VIP免费下载
文本内容

【文档说明】2022届湖南省普通高中学业水平考试合格性考试模拟试题(长郡版,高二物理)(答案).docx,共(3)页,48.213 KB,由envi的店铺上传

转载请保留链接:https://www.doc5u.com/view-cee401e6356ed74c482284d46a30ac97.html

以下为本文档部分文字说明:

2022年湖南省普通高中学业水平合格性考试模拟试卷(长郡版)物理参考答案一、选择题:本题共18小题,每小题3分,共54分。在每小题给出的四个选项中,只有一项是符合题目要求的。题号123456789答案DBBDBDCDA题号1011

12131415161718答案CCBDDABDD二、实验题:本题共3小题,每小题4分,每空2分,共12分。19.(1)C(2)D20.0.020.7521.4001000三、计算题:共3小题,共34分,解答应写出必要的文字

说明、方程式和重要的演算步骤,否则不得分。22.(10分)【解析】(1)物体做匀加速直线运动,根据加速度的定义式vat=··················································

···············································2分得1042a−=m/s2=3m/s2············································································1分

(2)根据位移公式02vvxvtt+==····························································2分得41022x+=m=14m··············································

······························2分(3)根据牛顿第二定律F=ma····································································2

分得F=2×3N=6N························································································1分23.(10分)【解析】(1)在外电路,电流方向由电源正极流向电源负极,故流过电阻R1的

电流方向是从a到b·················································································3分(2)将滑动变阻器滑片P向右移动少许,电路中的电阻增大,电流减小

,根据焦耳定律可知,电阻R1在相同时间内产生的热量将减小·················································3分(3)根据21PIR=热··················

······························································2分20.150P=热W=0.5W······················································

······················2分24.(14分)【解析】(1)小球在C处的动能为0,故小球在C处的机械能等于其重力势能011002J02JEmgh===...·····························

···································4分(2)小球在摆动过程中,不计空气阻力,只有重力做功,满足机械能守恒,即212mvmgh=·······························

··························································4分解得22100.2vgh==m/s=2m/s·······················································2分

(3)重力做功与路径无关,因A与C等高,故小球从A摆到C的过程中,重力对小球所做的功0W=.······················································································4分获得更多资源请扫码加

入享学资源网微信公众号www.xiangxue100.com

envi的店铺
envi的店铺
欢迎来到我的店铺
  • 文档 128952
  • 被下载 7
  • 被收藏 0
若发现您的权益受到侵害,请立即联系客服,我们会尽快为您处理。侵权客服QQ:12345678 电话:400-000-0000 (支持时间:9:00-17:00) 公众号
Powered by 太赞文库
×
确认删除?